The mode of the following frequency distribut | vedclass

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(C) The modal class is the class with the highest frequency. Here,the highest frequency is $11$,which corresponds to the class interval $15-20$. Thus,

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$\frac{215}{13}$

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(C) The modal class is the class with the highest frequency. Here,the highest frequency is $11$,which corresponds to the class interval $15-20$. Thus,$l = 15$,$h = 5$,$f_1 = 7$,$f_0 = 11$,and $f_2 = 2$. The formula for mode is: $	ext{Mode} = l + \left( \frac{f_0 - f_1}{2f_0 - f_1 - f_2} ight) 	imes h$ Substituting the values: $	ext{Mode} = 15 + \left( \frac{11 - 7}{2(11) - 7 - 2} ight) 	imes 5$ $	ext{Mode} = 15 + \left( \frac{4}{22 - 9} ight) 	imes 5$ $	ext{Mode} = 15 + \left( \frac{4}{13} ight) 	imes 5$ $	ext{Mode} = 15 + \frac{20}{13} = \frac{195 + 20}{13} = \frac{215}{13}$

Class	$0-5$	$5-10$	$10-15$	$15-20$	$20-25$	$25-30$
Frequency $(f_i)$	$3$	$4$	$7$	$11$	$2$	$5$

Class	$1 - 10$	$11 - 20$	$21 - 30$	$31 - 40$	$41 - 50$
$f_i$	$5$	$7$	$8$	$6$	$4$

The mode of the following frequency distribution is:

Class $0-5$ $5-10$ $10-15$ $15-20$ $20-25$ $25-30$

Frequency $(f_i)$ $3$ $4$ $7$ $11$ $2$ $5$

Similar Questions

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$f_i$ $5$ $7$ $8$ $6$ $4$

What is the relationship between mean,median,and mode for a moderately skewed distribution?

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In a moderately asymmetrical distribution,the mode and mean are $7$ and $4$ respectively. The median is:

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The mode of the following frequency distribution is: Class $0-5$ $5-10$ $10-15$ $15-20$ $20-25$ $25-30$ Frequency $(f_i)$ $3$ $4$ $7$ $11$ $2$ $5$